Agolf ball was thrown with a speed of 25 m/sec at an angle of 65° above the horizontal. what is the horizontal distance traveled by the ball before it hits the ground?

The horizontal distance traveled by the ball before it hits the ground is 48.85 meters.

Explanation:

It is given that,

Speed of golf ball, v = 25 m/s

Angle above horizontal or angle of projection, θ = 65°

We need to find the distance travelled by the ball before it hots the ground or in other words we need to find the range. It is given by R.

R = 48.85 m

So, the distance travelled by the ball before it hots the ground is 48.85 meters. Hence, this is the required solution.

+15-35=-20

going in opposite directions