Aproton is moving at 2.1 x 10 m/s clockwise through a constant and perpendicular magnetic field. the radius of curvature through the field is 0.6 meters. what is the strength of the magnetic field?

Explanation:

For this question the magnetic force provides the force required for the circular motion

Equating

Magnetic force = centripetal force

Bqvsinx = mv^2/r

as magnetic field is perpendicular x=90

Bqvsin90 = mv^2/r

Bq = mv/r

B= mv/rq

Then replace r= 0.6 , v= 2.1ms and mp from formula sheet and you can obtain B which is magnetic field intensity

+15-35=-20

going in opposite directions