After landing on an unfamiliar planet, a space explorer constructs a simple pendulum of length 53.0 cm . the explorer finds that the pendulum completes 99.0 full swing cycles in a time of 128 s . what is the magnitude of the gravitational acceleration on this planet? express your answer in meters per second per second.

12.4 m/s²

Explanation:

L = length of the simple pendulum = 53 cm = 0.53 m

n = Number of full swing cycles = 99.0

t = Total time taken = 128 s

T = Time period of the pendulum

g = magnitude of gravitational acceleration on the planet

Time period of the pendulum is given as

T = 1.3 sec

Time period of the pendulum is also given as

g = 12.4 m/s²

the simple machine has three main features. they are:

fulcrum is the center point or pivot point of the machine. effort is input force/ applied force. load is external force/ output.

the keisha 's machine labels are

x : load

y: fulcrum

z: lever