After falling from rest at a height of 32.3 m, a 0.556 kg ball rebounds upward, reaching a height of 22.1 m. if the contact between ball and ground lasted 1.62 ms, what average force was exerted on the ball?

F = 15771.6 N

Explanation:

Initial velocity of ball just before it will collide is given as

now for final speed of rebound we have

now the average force is given as

low freq = 100 mhz

low wavelength =101.7m

length = 3x10^8/freq

acceleration = (change in speed) / (time for the change)

change in speed = (20-120)= -100 m/s.

1.5 min = 90 sec

acceleration = -100/90 = -1.11 m/s^2.

we don't care about the 150kg or the 2,500 meters. they don't make any difference.

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