Physics, 13.07.2019 03:30 valenzueladomipay09u

Find the de broglie wavelength of a ball of mass 0.20 kg just before it strikes the earth after being |dropped from a building 50 m tall. important: step by step typed format preferred. if hand written, write clearly and legibly. be sure answer is correct.

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Answer from: naomicervero

Wavelength of the ball is $\lambda=1.05\times 10^{-34}\ m$

Explanation:

It is given that,

Mass of the ball, m = 0.2 kg

It strikes the Earth after being dropped from a building of 50 m tall, h = 50 m

In this time, the potential energy is converted to kinetic energy. On applying the conservation of energy as :

$\dfrac{1}{2}mv^2=mgh$

$v=\sqrt{2gh}$ .............(1)

The De-broglie wavelength of the ball is given by :

$\lambda=\dfrac{h}{mv}$

$\lambda=\dfrac{h}{m\sqrt{2gh}}$

$\lambda=\dfrac{6.63\times 10^{-34}\ J-s}{0.2\ kg\times \sqrt{2\times 9.8\ m/s^2\times 50\ m}}$

$\lambda=1.05\times 10^{-34}\ m$

Hence, this is the required solution.

Answer from: Quest

answer would be letter choice (a), a ball resting on a shelf. would be another example of potential energy > stored energy > not moving.

a ball spinning on a finger > kinetic energy > moving energy

a ball rolling on the ground > kinetic energy > moving energy

a ball flying through the air > kinetic energy > moving energy

hope that : )

Answer from: Quest

russian is not my first language, so i'm afraid i can't write out an answer in russian, but hopefully you can find a way to do so. here's my best translation of the problem: you're given a plot of a particle's position in one-dimensional space over time, and you're asked to find either the total distance traveled by the particle after 6 seconds had elapsed, or the total displacement of the particle after 6 seconds.

if you want the total distance traveled, you would first need to determine the particle's velocity as a function of time, then integrate that over the 6-second interval. we know the position function is quadratic with roots at 0 and 6, so we have

$x(t)=ax(x-6)$

where $a$ is unknown. because the position is parabolic, there is symmetry about the midpoint at $t=3$ , and we know that

$x(3)=10\implies -9a=10\implies a=-\dfrac{10}9$

so that the position function is

$x(t)=-\dfrac{10}9x(x-6)$

which means the velocity is

$v(t)=\dfrac{\mathrm dx}{\mathrm dt}=-\dfrac{20}9x+\dfrac{60}9$

then the total distance traveled is

$\displaystyle\int_{t=0}^{t=6}|v(t)|\,\mathrm dt=\left\{\int_{t-0}^{t=3}-\int_{t=3}^{t=6}\right\}v(t)\,\mathrm dt=20$

so the total distance traveled is 20 m.

on the other hand, if you want to find displacement: the particle starts at $x=0$ and ends at $x=0$ , so its displacement is 0.

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