Nresistors, each having resistance equal to 1 2, are arranged in a circuit first in series and then in parallel. what is the ratio of the power drawn from the battery for the two cases (i. e. p series: p parallel)? note: the battery supplies voltage v in both cases. a) 1: n b) 1: n2 c) n: 1 d) n2: 1

option (b)

Explanation:

Let the resistance of each resistor is R.

In series combination,

The effective resistance is Rs.

rs = r + R + R + + n times = NR

Let V be the source of potential difference.

Power in series

Ps = v^2 / Rs = V^2 / NR (1)

In parallel combination

the effective resistance is Rp

1 / Rp = 1 / R + 1 / R + + N times

1 / Rp = N / R

Rp = R / N

Power is parallel

Rp = v^2 / Rp = N V^2 / R     (2)

Divide equation (1) by equation (2) we get

Ps / Pp = 1 / N^2

ill do it for 100, also this isnt 80 its 40

the displacement produced by the body.  

the amount of force subjected to the body.  

the angle between the direction of force and displacement