Lectric device, which heats water by immersing a resistance wire in the water, generates 50 cal of heat per second when an electric potential difference of 12 v is placed across its leads. what is the resistance of the heater wire?

The resistance of the heater wire is of R= 0.68 Ω.

Explanation:

1 cal/s = 4.184 W

P= 50 cal/s = 209.2 W

V= 12V

P= V* I

I= P/V

I= 17.43 A

P= I² * R

R= P / I²

R= 0.68 Ω

come closer and become far apart and become steam/gas

when a device is used in a circuit in which the voltage is 81 v, the current flowing through the device is 3 a. what is the resistance of the device?

a. 27 ω

b. 40.5 a

c. 243 ω

d. 243 a

the correct answer is a. 27