Can someone me with this physics problem? i'd really appreciate any i can get!

560 m

Explanation:

"A projectile is fired at time t = 0.0 s from point 0 at the edge of a cliff, with initial velocity components of v₀ₓ = 30 m/s and v₀ᵧ = 100 m/s.  The projectile rises, and then falls into the sea at point P. The time of flight of the projectile is 25 s.  Assume air resistance is negligible.  What is the height of the cliff?"

Use constant acceleration equation in the y direction.

y = y₀ + v₀ t + ½ gt²

0 = h + (100 m/s) (25 s) + ½ (-9.8 m/s²) (25 s)²

h = 560 m

The height of the cliff is 560 m.

he . if i may ask what i your question exactly?

explanation:

trig 15.3 cos