Arock is dropped from a height of 2.5 meters. what is its velocity when it reaches the ground?

The velocity of the rock when it reaches the ground is

7

m

s

.

Explanation:

The formula we are using is

V

2

2

=

V

2

1

+

2

a

Δ

d

=> Where

V

is the velocity in

m

s

.

=> Where

a

is acceleration in

m

s

2

.

=> Where

Δ

d

is the change in displacement in

m

.

So now we just plug in the numbers.

V

2

2

=

V

2

1

+

2

a

Δ

d

=

0

+

2

(

9.8

)

(

2.5

)

=

√

49

=

7

The velocity of the rock when it reaches the ground is

7

m

s

.

explanation:

a fuel engine ( known as a gasoline engine in american english )is an internal combustion engine with spark ignition, designed to run on petrol (gasoline) and similar volatile fuels.

another example of kinetic energy would be,

kinetic energy   >     moving energy

answer   >   letter choice (c),   a hammer falling off a table.

hope that !                                         : )