An attacker at the base of a castle wall 3.85 m high throws a rock straight up with speed 8.50 m/s from a height of 1.45 m above the ground.
(a) will the rock reach the top of the wall? yes no correct: your answer is correct.
(b) if so, what is its speed at the top? if not, what initial speed must it have to reach the top? m/s
(c) find the change in speed of a rock thrown straight down from the top of the wall at an initial speed of 8.50 m/s and moving between the same two points. m/s
(d) does the change in speed of the downward-moving rock agree with the magnitude of the speed change of the rock moving upward between the same elevations? yes no correct: your answer is correct.
(e) explain physically why it does or does not agree.

answer; (d) spontaneous processes are characterized by the overall conversion of order to disorder;

answer: i'm not sure which is which for i get confused on it all the time but i can tell you that the answer lies with the convex and concave devices. i hope this you. have a good day and best of luck to you!

explanation:

attach the statements so i can answer : )

scattering of light by tiny particles in air to produce the colors we see on sky, is dependent on the following factors:

(i) wavelength of light

(ii) size of the scattering particle  

(iii) distance traveled by light through the atmosphere.

according to rayleigh's law of scattering, the amount of scattering is inversely proportional to the fourth power of its wavelength. shorter the wavelength, greater is its scattering. hence violet/blue light is scattered more than red.

sun's light is a composite light ( visible light) with wavelengths in the range 400 nm (violet) to 700 nm (red). as sunlight passes through our atmosphere, the molecules of air scatter light according to their wavelengths. during sunrise and sunset, the sun's position is below the horizon. hence light from the sun travels a greater distance in the atmosphere when compared to its position a noon.

as sunlight enters the earth's atmosphere, blue light is scattered away and at the end of its journey in the sky, only red and orange wavelengths remain in the beam.

hence at sunrise and sunset, the sky appears reddish orange.