Find the proton separation energy of: (a) he; (b) 12c (c) 40ca

a) Sp = 19.82 MeV

b) Sp = 15.96 MeV

c) Sp = 26.21240 MeV

Explanation:

He atomic number = 2

He mass number = 4

He molar mass = 4.002602 u

Element with 2-1 atomic number = 1 and Element with mass number = 4-1 = 3 is Tritium

Tritium molar mass = 3.0160492 u

Hydrogen molar mass = 1.00784 u

separation energy

Sp=(3.0160492+1.00784-4.002602)(931.50 MeV/u)     (1 u = 931.5 MeV)

a) Sp = 19.82 MeV

Carbon atomic number 6

Mass number = 12

Element with 6-1 atomic number = 5 and Element with mass number = 12-1 = 11 is Boron 11

Sp=(mass of boron 11+mass of hydrogen+mass of carbon)×931.5

Sp=(11.009305+1.00784-12)×931.5

b) Sp = 15.96 MeV

Calcium atomic number = 20

Calcium mass number = 40

Sp=(mass of potassium+mass of hydrogen+mass of calcium)×931.5

Sp=(39.0983+1.00784-40.078)×931.5

c) Sp = 26.21240 MeV

  1.the balanced   chemical equation is as below

cu +   2 ag(no)₃ → cu(no₃)₂   +2 ag

2.the   much silver   produced   is   50.9 g

step 1: find the   moles of cu

moles =   mass÷   molar mass

  from periodic table the molar mass of cu = 63.5 g/mol

moles is therefore = 15.00 g÷ 63.5 g/mol = 0.236   moles

step 2: use the mole ratio to determine the   moles of ag

from equation above   cu: ag   is 1: 2

therefore the moles of ag   =0.236   moles   x 2/1 =0.472   moles

step 3: find the mass   of ag

mass = moles x molar mass

from periodic table   the molar mass of ag =107.87 g/mol

mass   = 0.472   moles x 107.87 g/mol = 50.9 g

3.   the   much   silver   collected worth is   1.797 oz

  convert   50.9 g   to oz

that is   1 gram = 0.0353 oz

          50.9 grams =?   oz

by cross multiplication

={(50.9 grams x 0.0353 oz) / 1   gram}   =1.797 oz