What should be the spring constant k of a spring designed to bring a 1300 kg car to rest from a speed of 95 km/h so that the occupants undergo a maximum acceleration of 5.0g?

We have that for the Question ,it can be said that he spring constant k of a spring designed to bring a 1300 kg car to rest from a speed of 95 km/h so that the occupants undergo a maximum acceleration of 5.0g is

k=4449.3Nm^{-1}

From the question we are told

What should be the spring constant k of a spring designed to bring a 1300 kg car to rest from a speed of 95 km/h so that the occupants undergo a maximum acceleration of 5.0g?

Generally the equation for the  angular frequency is mathematically given as

Generally the equation for the  spring constant k is mathematically given as

k=4449.3Nm^{-1}

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Spring constant, k = 4485.24 N/m

Explanation:

It is given that,

Mass of the car, m = 1300 kg

Speed of the car, v = 95 km/h = 26.38 m/s

Acceleration, a = 5 g

We need to find the spring constant k of the spring such that,

m a = k x

.........(1)

The elastic potential energy is balanced by the kinetic energy of the spring such that,

k = 4485.24 N/m

So, the spring constant of the spring is 4485.24 N/m. Hence, this is the required solution.  

force tends to be low and long diustance masses are high

weight of the box is given as

here this is placed on the inclined of angle 42 degree

now this weight will have two components one is along the incline other is perpendicular to it

so here we need to apply a force parallel to incline opposite to its component of weight

so here the component of weight is given as

here we have

so it requires 75 n force to move it upwards