A3.00 kg object is moving in the xy plane, with its x and y coordinates given by x = 5t³ ! 1 and y = 3t ² + 2, where x and y are in meters and t is in seconds. find the magnitude of the net force acting on this object at t = 2.00 s.

The net force acting on this object is 180.89 N.

Explanation:

Given that,

Mass = 3.00 kg

Coordinate of position of

Coordinate of position of

Time = 2.00 s

We need to calculate the acceleration

For x coordinates

On differentiate w.r.to t

On differentiate again w.r.to t

The acceleration in x axis at 2 sec

For y coordinates

On differentiate w.r.to t

On differentiate again w.r.to t

The acceleration in y axis at 2 sec

The acceleration is

We need to calculate the net force

The magnitude of the force

Hence, The net force acting on this object is 180.89 N.

what is the actual question though?