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.....(1)![\text{Average atomic mass}=[(19.99\times 0.9092)+(20.99\times 0.0026)+(21.99\times 0.0882)]](/tpl/images/0105/8735/94c3c.png)
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An element has the following natural abundances and isotopic masses: 90.92% abundance with 19.99 am...
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