Two particles, one with charge -5.45 uc and one with charge 3.55 uc, are 4.34 cm apart. what is the magnitude of the force that one particle exerts on the other?

Force, F = 92.02 N

Explanation:

It is given that,

Charge 1,

Charge 2,

Distance between two charges, d = 4.35 cm = 0.0435 m

We need to find the magnitude of the force that one particle exerts on the other. It is given by :

F = -92.02 N

So, the force acting between two particles is 92.02 N. Hence, this is the required solution.

Explanation:

As we know that the force between two charge particles is given by

here we know that

now the distance between the two charges is

r = 4.34 cm

now from the formula of electrostatic force we will have

the average speed is 24.57 km/hr