Acar is traveling at 50 mi/h when the brakes are fully applied, producing a constant deceleration of 48 ft/s2. what is the distance covered before the car comes to a stop

Distance covered by the car is 56.01 feet.

Explanation:

It is given that,

Initial velocity, u = 50 mi/h = 73.33 ft/s

Constant deceleration of the car,

Final velocity, v = 0

Let s is the distance covered before the car comes to rest. It can be calculated using third equation of motion as :

s = 56.01 ft

So, the distance covered before the car comes to a stop is 56.01 feet. Hence, this is the required solution.

what is the speed of a softball that travels 20m in 2secs

speed = 20/2 = 10 m/s