When we found the electric field of a charged ring at a point on the ring's central axis, which did we sum the field components perpendicular to the central axis the magnitudes of the field vectors the field components parallel to the central axis

initial speed when it is dropped is 150 ft/s

now at the same moment the acceleration due to gravity is perpendicular to its velocity

so as we know that

now we have centripetal acceleration a = 32 ft/s^2 as its perpendicular to velocity

while tangential acceleration at the same moment will be zero

so

now radius of curvature is given as

so the radius of curvature just after it is dropped is 703.125 ft

conduct current i mean it makes sense