A10.1-g bullet is fired into a stationary block of wood having mass m = 5.03 kg. the bullet imbeds into the block. the speed of the bullet-plus-wood combination immediately after the collision is 0.593 m/s. what was the original speed of the bullet? (express your answer with four significant figures.)

The original speed of the bullet was of V1= 295.9187 m/s.

Explanation:

m1= 10.1 g = 0.0101 kg

m2= 5.03 kg

V2= 0.593 m/s

V1= ?

m1*V1 = (m2+m1)*V2

V1= [(m2+m1) * V2] / m1

V1= 295.9187 m/s

whichever one it is, it's definitely not one that you included on the list you provided.

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i have found an answer to your question but use it as information.

information: because weak acids/bases have low concentration of hydrogen ions, the addition of water has a large impact on the ph. 2. a difference in 1 unit is a 10x difference in concentration for example; a liquid with ph of 3 is 10x more acidic than a liquid with a ph of 4. therefore, a liquid with a ph of 3 is stronger.

best of luck!