Abaseball player wants to hit a home run over the wall of a stadium. he hits the ball 0.751 m above the ground with at an angle of 30 degrees above the horizontal and a speed of 37.5 m/s. what is the tallest wall the player can clear if the wall is 150 m away?

18.67 m wall

Explanation:this is projectile.

For Max height,

H = v²sin²©/2g

H= (37.5)²sin²(30)/(2*9.81)

H = 17.919 m

But he is standing 0.751 m above ground, so total height = 17.919+0.751= 18.67m

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