Physics, 23.07.2019 03:30 jojosiwa6

If the action potential starts with a potential difference of +40.0 mv, and the length constant of the axon is 2.00 mm, how far from the site of the stimulus will the potential difference across the membrane drop to 1.00 mv (assuming the action potential is not regenerated)?

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answer: the rock sample is a sedimentary rock.

explanation:

it is given that:

mass of rock sample, m = 2.7 g

volume of rock sample, $v = 1.1 cm^{3}$

so, density of rock sample will be

$density = \frac{mass}{volume}$

$\rho =\frac{2.7}{1.1}g/cm^{3}\\\\\rho =2.45 g/cm^{3}$

since, the density of rock sample is $2.45 g/cm^{3}$ . hence, the rock sample is a sedimentary rock, whose densities varies between $2g/cm^{3} - 2.6 g/cm^{3}$ .

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the electric field is a “force field” around a charged object that illustrates the direction the electric force would push an imaginary

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Well the magnitude of its acceleration related to that car starts with the oil change like when you have to change the oil in your car you have to make sure that your precious car is starting really propley and very well

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If the action potential starts with a potential difference of +40.0 mv, and the length constant of t...

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