A2.0-m long conducting wire is formed into a square and placed in the horizontal x-y plane. a uniform magnetic field is oriented 30.0° above the horizontal with a strength of 9.0 t. what is the magnetic flux through the square?

1.13 Wb

Explanation:

First of all, we need to find the area enclosed by the coil.

The perimeter of the square is 2.0 m, so the length of each side is

So the area enclosed by the coil is

Now we can calculate the magnetic flux through the square, which is given by

where

B = 9.0 T is the strength of the magnetic field

is the area of the coil

is the angle between the direction of the magnetic field and the normal to the coil; since the field is oriented 30.0° above the horizontal and the coil lies in the horizontal plane, the angle between the direction of the magnetic field and the normal to the coil is

So the magnetic flux is