Aball is thrown horizontally from the top of a 60.0-m building and lands 100.0 m from the base of the building. ignore air resistance. how long is the ball in the air?

3.50 s

Explanation:

The movement of the ball has a vertical component and a horizontal component. The vertical movement is can be represented through a Uniformly Accelerated Motion (constant acceleration), while the horizontal movement can be represented through a Uniform Motion (constant speed).

We can find the time (t) that the ball was in the air just by considering the vertical movement. The initial vertical speed (v₀) is 0 (the ball is thrown horizontally), the vertical distance traveled (y) is 60.0 m, and the acceleration (a) is that of gravity. Then.

y = 1/2 × a × t²

t = √(2 × y/ a) = √(2 × 60.0 m/ 9.81 m/s²) = 3.50 s

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