When two resistors are wired in series with a 12 v battery, the current through the battery is 0.33 a. when they are wired in parallel with the same battery, the current is 1.60 a. part a what are the values of the two resistors?

If R₂=25.78 ohm, then R₁=10.58 ohm

If R₂=10.57 then R₁=25.79 ohm

Explanation:

R₁ = Resistance of first resistor

R₂ = Resistance of second resistor

V = Voltage of battery = 12 V

I = Current = 0.33 A (series)

I = Current = 1.6 A (parallel)

In series

In parallel

Solving the above quadratic equation

∴ If R₂=25.78 ohm, then R₁=10.58 ohm

If R₂=10.57 then R₁=25.79 ohm

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