Acharge of q= +15 uc moves in a northeast direction with a speed 5 m/s, 25 degrees east of a magnetic field, pointing north, with a magnitude of 0.08 t. find the force (magnitude and direction) on the charge.

Explanation:

It is given that,

Magnitude of charge,

It moves in northeast direction with a speed of 5 m/s, 25 degrees East of a magnetic field.

Magnetic field,

Velocity,

We need to find the magnitude of force on the charge. Magnetic force is given by :

Since,

So, the force acting on the charge is and is moving in positive z axis. Hence, this is the required solution.

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hope this you out ^w^

double the distance = divide strength by 4