Two point charges of +1.0 μc and -2.0 μc are located 0.50 m apart. what is the minimum amount of work needed to move the charges apart to double the distance between them? (k = 1/4π ε0 = 8.99 × 109 n · m2/c2)

The minimum amount of work needed to move the charges apart to double the distance between them is 0.018 J.

We know to change the position of a charge from one point to another work done can be written as,

Also, we know that the potential energy can be written as,

Given to us

q₁ = +1.0 μC  = 1 x 10⁻⁶ C

q₂ =  -2.0 μC = 2 x 10⁻⁶ C

m

= 0.5 m

Substitute the values,

Hence, the minimum amount of work needed to move the charges apart to double the distance between them is 0.018 J.

Learn more about Work:

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W = 0.018 J

Explanation:

As we know that work done to change the position of charge is given as change in the potential energy of the system

here we can say

so here we have

so we can say

now plug in all values in it

in simple terms, the principle states that the buoyancy force on an object is equal to the weight of the fluid displaced by the object, or the density of the fluid multiplied by the submerged volume times the gravitational acceleration, g. this is also known as upthrust.