Give a rail gun shown below with b-3.0t and rail spacing of 25 cm. a discharging capacitor supplies a current of 100 ka. 5) a. what is the acceleration if the bar has a mass of 0.25 kg. [3 x 10s m/s? ] h. what is the bars speed at the end of a 2.75 m long track [1.2 km/s ]

Explanation:

It is given that,

Magnetic field, B = 3 T

Length of the spacing, L = 25 cm = 0.25 m

Current,

Mass of the bar, m = 0.25 kg

(a) Magnetic force is given by :

F = 75000 N

Using second law of motion,

F = m × a

(B) Let v is the speed of the bars at the end of long track. Initial speed of the bar is 0. Using third equation of motion as :

v = 1284.52 m/s

or

v = 1.2 km/s

So, the speed of the bar at the end is 1.2 km/s. Hence, this is the required solution.

the total distance that martina travels that day is

(distance from home to mom's office) plus (distance from mom's office to school)

plus (distance from school to library) plus (distance from library to friend's house)

plus (distance from friend's house to martina's house).

(we don't know what any of these distance actually is.)