If the net vertical impulse of a 580 n person is 165 ns over 0.5 s, what was the average net vertical force produced? if her initial vertical velocity was –0.200 m/s, what was her vertical take-off velocity?

1) The average force delivered is the impulse divided by the elapsed time:

F = J/Δt

F is the average force, J is the impulse, and Δt is the elapsed time.

Given values:

J = 165Ns

Δt = 0.5s

Plug in the values and solve for F:

F = 165/0.5

F = 330N

2) The impulse J is the person's change in momentum Δp:

J = Δp

The person's momentum is the product of their mass and velocity:

p = mv

Assuming the person's mass stays constant, their change in momentum is equal to their mass multiplied by their change in velocity:

Δp = mΔv

By definition the change in velocity is the difference of the final and initial velocities:

Δv = v_{f} - v_{i}

Knowing all this, we therefore have this equation:

J = m(v_{f} - v_{i})

We do not know the person's mass yet, but we do know her weight, and the weight is given by:

W = mg

W is the weight, m is the mass, and g is the acceleration due to earth's gravity near its surface

Given values:

W = 580N

g = 9.81m/s²

Plug in the values and solve for m:

580 = m×9.81

m = 59.1kg

Now to find the take-off velocity we use this equation:

J = m(v_{f} - v_{i})

Given values:

J = 165Ns

m = 59.1kg

v_{i} = -0.200m/s

Plug in these values and solve for v_{f}:

165 = 59.1(v_{f} + 0.200)

v_{f} + 0.200 = 2.79

v_{f} = 2.59m/s

answer: d. a cme increases the amount of energy in the solar wind

explanation:

coronal mass ejections, also called cmes, are large clouds of plasma and magnetic field that erupt from the sun. only when the cloud is aimed at earth will the cme hit earth and therefore cause impacts. high-speed solar wind streams come from areas on the sun known as coronal holes.

more than, less

less than, more