A12000 kg boat is moving 4.25 m/s. its engine pushes 9200 n forward, but the current pushes back at 12,500 n. how much times does it take the boat to stop?

15.5 seconds

Explanation:

Apply Newton's second law:

∑F = ma

-12500 + 9200 = (12000) a

a = -0.275 m/s²

v = at + v₀

0 = (-0.275) t + 4.25

t = 15.5 s

It takes the boat 15.5 seconds to stop.

true

explanation:

where is the circuit diagram ?