An airplane of mass 5000 kg flies in a straight line at steady speed of 70 m/s. wind resistance pushes backwards on the airplane with a force of 2000 newtons. is the forward force that the engine exerts on the airplane greater than, less than, or equal to 2000 n? explain.

Answer to the question:

Explanation:

The forward force that the engine exerts on the airplane ar equal to 2000 N because there is no acceleration on the movement of the airplane.

Fengine - Fwind = m* a

with a=0 m/s²

Fengine = Fwind

see the picture for the vector

the magnitude of the vector by pythagorean theorem

r = √( (-10)^2 + (3)^2 ) = √109

magnitude = √109 units

the direction angle between vector and x-axis is

tan^(-1)(3/10) = 16.699

so the direction is approximately 16.7 degrees north of west