Acharge particle moving through a magnetic field experiences a magnetic force. what is the angle between the magnetic field and the force on the particle?

The magnetic force on a moving charged particle is given by:

F = qv×B

F is the magnetic force vector, q is the charge, v is the velocity vector, and B is the magnetic field vector. Note that we are taking the cross product of qv and B, not multiplying scalar quantities.

The cross product of two vectors gives a third vector which is perpendicular to the original two vectors. The very nature of taking a cross product means that F will always be perpendicular to B, i.e. the angle between F and B will always be 90°.

he . if i may ask what i your question exactly?

explanation:

pythagoras' theorem

square root (-5^2+9^2)

square root (25+81)

square root (106)

angle is tan^-1(9/5)

neg x, pos y