Apositively-charged object with a mass of 0.129 kg oscillates at the end of a spring, generating elf (extremely low frequency) radio waves that have a wavelength of 3.86 × 10^7 m. the frequency of these radio waves is the same as the frequency at which the object oscillates. what is the spring constant of the spring?

308 N/m

Explanation:

Given

mass

wavelength

We know frequency =

f=7.772 Hz

As the frequency of radio waves is same as the frequency at which object oscillates

the old price per ounce is c/4.

the new price per ounce is c/3.6.

the ratio of the old price to the new one is

(c/4)/(c/3.6) = (c/c)×(3.6/4) = 0.9 . . = 9/10 . . "nine tenths" in either form