Calculate the speed (in m/s) of an electron and a proton with a kinetic energy of 1.25 electron volt (ev). (the electron and proton masses are me = 9.11 ✕ 10−31 kg and mp = 1.67 ✕ 10−27 kg. boltzmann's constant is kb = 1.38 ✕ 10−23 j/k.)

6.63 x 10⁵ m/s

0.16 x 10⁵ m/s

Explanation:

= mass of the electron = 9.11 x 10⁻³¹ kg

= mass of the proton = 1.67 x 10⁻²⁷ kg

= speed of electron

= speed of proton

= Kinetic energy of electron = 1.25 eV = 1.25 x 1.6 x 10⁻¹⁹ J

Kinetic energy of electron is given as

= 6.63 x 10⁵ m/s

Kinetic energy of proton is given as

= 0.155 x 10⁵ m/s

explanation: in any substance/object, the particles inside it (atoms/molecules) constantly move in random directions and with random speeds (this motion is called brownian motion). as a result, the particles have some kinetic energy (which is proportional to the temperature of the substance).

explanation:

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explanation:

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