A6.25-kg bowling ball moving at 9.4 m/s collides with a 0.875-kg bowling pin, which is scattered at an angle of \theta =83.5 degrees from the initial direction of the bowling ball, with a speed of 17.5 m/s.(part a) calculate the direction, in degrees, of the final velocity of the bowling ball. this angle should be measured in the same way that \theta is.(part b) calculate the magnitude of the final velocity, in meters per second, of the bowling ball.

A)

B) v = 9.47 m/s

Explanation:

Given:

mass of the bowling ball, m₁ = 6.25 kg

Initial velocity of the ball, v₁ = 9.4 m/s

mass of bowling pin, m₂ = 0.875 kg

velocity of the pin, v₂ = 17.5 m/s

Angle of scatter, Θ = 83.5°

a)The direction of the final velocity of the ball (∅)

on substituting the values in the above equation, we get

or

or

or

B) From the concept of conservation of momentum

we have

on substituting the values

we get

hence, the magnitude of the final velocity

v = 9.47 m/s

as we know our atmosphere or air have different levels. every level has other gasses, and every gas has another permeability. when the light comes from lower permeability to higher permeability, it changes its direction. so that means that when the light comes from the moon to the earth, it changes it's direction many more times. it basically means that the shape of the light part of the moon is changed on the earth.

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