Astrip of copper 150 µm thick and 4.50 mm wide is placed in a uniform magnetic field of magnitude b = 0.74 t, that is perpendicular to the strip. a current i = 18 a is then sent through the strip such that a hall potential difference v appears across the width. calculate v. (the number of charge carriers per unit volume for copper is 8.47 × 1028 electrons/m3.)

V = 6.55*10^{-6} v

Explanation:

The number density can be determined by using below formula:

where,

B  is uniform magnetic field 0.74

i is current 18 A

V is hall potential difference

l is thickness 150 MICRO METER

e is electron charge 1.6 *10^{-19} C

therefore V can be determined as

V = 6.55*10^{-6} v

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explanation: