A0.333 kg particle with an initial velocity of 1.89 m/s is accelerated by a constant force of 1.64 n over a distance of 0.281 m. use the concept of energy to determine the final velocity of the particle. (it is useful to double-check your answer by also solving the problem using newton's laws and the kinematic equations.)

2.5 m/s

Explanation:

m = 0.333 kg

u = 1.89 m/s

F = 1.64 N

S = 0.281 m

Let the final velocity is v.

By energy conservation

Work done = Change in kinetic energy

F x S = 1/2 m (v^2 - u^2)

1.64 x 0.281 = 0.5 x 0.333 (v^2 - 1.89^2)

2.767 = v^2 - 3.5721

v^2 = 6.339

v = 2.5 m/s

By using kinematics

Let a be the acceleration

a = F / m = 1.64 / 0.333 = 4.925 m/s^2

Use third equation of motion

v^2 = u^2 + 2as

v^2 = 1.89^2 + 2 x 4.925 x 0.281

v^2 = 6.339

v = 2.5 m/s

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the independent variable, the one that is intentionally manipulated, is whether or not the car hits the barrier.

the dependent variable, the one that you measure the response in, is the distance that the washers travel.