An lsu football defender is 6 m behind a georgia tech receiver who has the football and is d meters from making a touchdown. if the lsu player is running at 5 m/s and the receiver is running at 4 m/s, what is the furthest distance, d, that the tech player can be from the goal line and still make a touchdown?

furthest distance d = 24 m

Explanation:

LSU football defender = 6 m

LSU player is running =  5 m/s

receiver running =  4 m/s

to find out

furthest distance d

solution'we take here 2 equation

distance = velocity × time

d = 4 × t      1

6+ d = 5 × t   2

so now put d value in equation 2 we get time

6+ 4t = 5 × t  

t = 6 sec

now this t value put in equation 1

d = 4 × t  

d = 4 (6)

distance = 24 m

so furthest distance d = 24 m

step-by-step explanation:

we are given

we have to simplify it

firstly, we will factor it

now, we can cancel like terms

now, we can combine it

so, we get

iron would move it is magnetic there is a mag field around the current in the wire