Amass weighing 20 pounds stretches a spring 6 inches. the mass is initially released from rest from a point 6 inches below the equilibrium position. (a) find the position x of the mass at the times t = π/12, π/8, π/6, π/4, and 9π/32 s. (use g = 32 ft/s2 for the acceleration due to gravity.)

Since the spring mass system will execute simple harmonic motion the position as a function of time can be written as

'A' is the amplitude = 6 inches (given)

is the natural frequency of the system

At equilibrium we have

Applying values we get

thus natural frequency equals

Thus the equation of motion becomes

At time t=0 since mass is at it's maximum position thus we have

Thus the position of mass at the given times is as follows

1) at

2) at

3) at

4) at

5) at

the focus of lesson 1 is newton's first law of motion - sometimes referred to as the law of inertia. newton's first law of motion is often stated as. an object at rest stays at rest and an object in motion stays in motion with the same speed and in the same direction unless acted upon by an unbalanced force.

explanation:

are their multiple choices ?

explanation: