Physics, 01.08.2019 01:20 pedropaulofpedrosapp
The crate, which sets on a 10 degree incline, has a weight of 3433.5 n and is subjected to a towing force p acting at a 20 degree angle with the horizontal. if the coefficient of static friction is µs = 0.5, determine the force p needed to just start the crate moving down the plane.
Answers: 2
![\mu[Wcos10^{0}-Psin30^{o}] =Pcos30^{o}+Wsin10^{0}\\\\\mu Wcos10^{0}- \mu Psin30^{o} =Pcos30^{o}+Wsin10^{0}\\\\\mu Wcos10^{0}- Wsin10^{0}=Pcos30^{o}+\mu Psin30^{o} \\\\P=W\frac{\mu cos10^{0}- sin10^{0}}{cos30^{o}+\mu sin30^{o}} \\\\P=3433.5\frac{0.5 \times cos10^{0}- sin10^{0}}{cos30^{o}+0.5 \times sin30^{o}}\\\\P=980.66\\\\ P = 981 N](/tpl/images/0156/3921/34ec4.png)
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The crate, which sets on a 10 degree incline, has a weight of 3433.5 n and is subjected to a towing...
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