Aproton, traveling with a velocity of 4.5 × 106 m/s due east, experiences a magnetic force that has a maximum magnitude of 8.0 × 10−14 n and a direction of due south. what are the magnitude and direction of the magnetic field causing the force?

Magnetic field, B = 0.11 i (in k direction)

Explanation:

It is given that,

Velocity of the proton,

Magnetic force, (due south)

The magnetic force acting on the electron is given by :

(-j) = (i) × (B)

q is the charge on proton

B = 0.11

So, the magnitude of 0.11 T is acting on the proton in and is acting directed upward above the plane. Hence, this is the required solution.

if they have a finite resultant

answer: 31, 5556. 952 seconds