You are holding a 5.0-kg gold bar under water. how heavy does it feel? (i. e. what is the bar’s weight under water? ) the density of water is ρw = 1000 kg/m3 and the density of gold is ρg = 19,300 kg/m3 .

It will feel 4.85% lighter.

Explanation:

Normal weight of the gold bar = 5.0 × 9.81 = 49.05 N

The weight of the gold bar would be reduced because of the buoyant force acting upwards.

weight of the gold bar under water = normal weight - weight of the water displaced by the gold bar.

first, we need to find the volume (V) of the gold bar.

Percentage of decrease in weight

answer would be letter choice (a),   a ball resting on a shelf. would be another example of potential energy   >   stored energy > not moving.

a ball spinning on a finger   >   kinetic energy > moving energy

a ball rolling on the ground   >   kinetic energy   > moving energy

a   ball flying through the air   > kinetic energy   >   moving energy

hope that                                         : )