When karl kaveman adds chilled grog to his new granite mug, he removes 10.9 kj of energy from the mug. if it has a mass of 625 g and was at 25°c, what is its new temperature? specific heat capacity of granite = 0.79 j/(g·k)

3°C

Explanation:

We can that heat Q=m dT

Where m is the mass = specific heat capacity

dT = Temperature difference

here we have given m=625 g =.625 kg

specific heat of granite =0.79 J/(g-K) = 0.79 KJ/(kg-k)

=25°C

we have to find

we have also given Q=10.9 KJ

10.9=0.625×0.79×(25-)

25- =22

=3°C

50 inches should be the resultant vector

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