1. a car drives by at 20mph, with a violinist in it playing a song. the speed of sound is 343 m/s. the violin is actually playing at 800hz, what frequency do you hear before and after the car passes you?

frequency when car is approaching comes out to be 821 Hz

car is moving away from the object comes out to be 780 Hz

Explanation:

car speed = 20 mph = 8.94 m/s

speed of sound = 343 m/s

violin frequency = 800 Hz

when car is approaching:

when car is moving away

hence the frequency when car is approaching comes out to be 821 Hz

and when the car is moving away from the object comes out to be 780 Hz

we have been given a quadratic function and we need to restrict the domain such that it becomes a one to one function.

we know that vertex of this quadratic function occurs at (5,2).

further, we know that range of this function is .

if we restrict the domain of this function to either or , it will become one to one function.

let us know find its inverse.

upon interchanging x and y, we get:

let us now solve this function for y.

hence, the inverse function would be if we restrict the domain of original function to and the inverse function would be if we restrict the domain to .