A1.40-kg particle moves in the xy plane with a velocity of v with arrow = (4.00 î − 3.30 ĵ) m/s. determine the angular momentum of the particle about the origin when its position vector is r with arrow = (1.50 î + 2.20 ĵ) m.

the angular momentum of the paticle is 8.4i - 10.2j.

Explanation:

the angular momentum is given by:

L = m×v×r

  = (1.40)×(4.00i - 3.30j)×(1.50i + 2.20j)

   = (1.40)×[(4.00×1.50)i - (3.30×2.20)j]

   = (1.40)×(6i - 7.26j)

   = 8.4i - 10.2j

Therefore, the angular momentum of the paticle is 8.4i - 10.2j.

the independent variable, the one that is intentionally manipulated, is whether or not the car hits the barrier.

the dependent variable, the one that you measure the response in, is the distance that the washers travel.

not too sure thinking all accelerations are pointed down