Aprofessional golfer is examining a video of a practice swing. the high‑speed footage shows that his club is in contact with the ball (which was initially at rest on the tee) for only δ=0.971δt=0.971 ms, and the radar gun clocks the speed of the ball as =161vb=161 mph after it comes off the club. the golf ball has a mass of =45.9mb=45.9 g. what is the magnitude of the impulse imparted to the ball by the club?

The impulse imparted to the ball by the club is 3.30 kg m/s.

Explanation:

Given that,

Time = 0.971 ms

Final speed of ball =161 mph

mass of ball = 45.9 g

We need to calculate the impulse

Impulse is equal to the change in momentum

Using formula of impulse

Where, m = mass of ball

= final velocity of ball

Put the value into the formula

Hence, The impulse imparted to the ball by the club is 3.30 kg m/s.

potential energy is directly proportional to height.

more height = more potential energy.

greatest increase in height = greatest increase in potential energy

where are the points with the greatest increase in height ?

has to be c-e or d-e .