An electron undergoes a transition from the n=3 state to the ground state in a hydrogen atom. calculate the wavelength of the photon emitted as a result of this transition in the units of meters. an excellent response will include the appropriate relationship along with consideration of dimensional analysis , scientific notation, and consideration of significant figures.

Explanation:

As we know by Bohr's Postulates that when electron makes transition from higher excited state to lower excited state then energy difference of two levels is released in the form of photons.

So we can say

here we know that energy of nth excited state in any atom is given as

here for hydrogen atom z = 1

also we know that

now from above equation we have

scattering of light by tiny particles in air to produce the colors we see on sky, is dependent on the following factors:

(i) wavelength of light

(ii) size of the scattering particle  

(iii) distance traveled by light through the atmosphere.

according to rayleigh's law of scattering, the amount of scattering is inversely proportional to the fourth power of its wavelength. shorter the wavelength, greater is its scattering. hence violet/blue light is scattered more than red.

sun's light is a composite light ( visible light) with wavelengths in the range 400 nm (violet) to 700 nm (red). as sunlight passes through our atmosphere, the molecules of air scatter light according to their wavelengths. during sunrise and sunset, the sun's position is below the horizon. hence light from the sun travels a greater distance in the atmosphere when compared to its position a noon.

as sunlight enters the earth's atmosphere, blue light is scattered away and at the end of its journey in the sky, only red and orange wavelengths remain in the beam.

hence at sunrise and sunset, the sky appears reddish orange.

multiple allele inheritance is traits controlled by more than 2 alleles (ex: pigeons having 3 alleles of one gene govern their feather color).