Atechnician at a semiconductor facility is using an oscilloscope to measure the ac voltage across a resistor in a circuit. the technician measures the oscillating voltage to be a sine wave with a peak voltage of 6.25 v but must record the rms voltage on a report. what value should be reported?

The rms voltage on a report is 4.42 V.

Explanation:

Given that,

Peak voltage = 6.25 V

We need to calculate the rms voltage

The rms voltage is equal to the peak voltage divided by square root of 2.

Using formula of rms voltage

Where, = Peak voltage

Put the value into the formula

Hence, The rms voltage on a report is 4.42 V.

the simple machine has three main features. they are:

fulcrum is the center point or pivot point of the machine. effort is input force/ applied force. load is external force/ output.

the keisha 's machine labels are

x : load

y: fulcrum

z: lever