Assume your eye has an aperture diameter of 3.00 mm at night when bright headlights are pointed at it. 1) at what distance can you see two headlights separated by 1.80 m as distinct? assume a wavelength of 550 nm, near the middle of the visible spectrum. (express your answer to two significant figures.)

The distance is 6259.31 meters.

Explanation:

We shall use the Reyligh criterion to solve the problem

For diffraction due to circular aperture we have

Assuming that human eye is circular we have

Applying the given values we have

8.1 x 10³ m

Explanation:

D = diameter of the aperture =3 mm = 0.003 m

x = distance between the two headlights = 1.80 m

λ = wavelength of the visible spectrum = 550 x 10⁻⁹ m

d = distance of the headlights from eyes = ?

Using Reyleigh's criterion,

d = 8047.7 m

d = 8.1 x 10³ m

frequency or wavelenth of em radiation in a vacuum

hi,

what occurs during a solar eclipse?

there are small tides across earth.

the moon is between earth and the sun.

p.s. im not sure if the first answer is correct because during a solar ecliphse there are spring tides and i dont know if they are the same.