The only force acting on a 2.5 kg canister that is moving in an xy plane has a magnitude of 3.0 n. the canister initially has a velocity of 2.3 m/s in the positive x direction, and some time later has a velocity of 6.4 m/s in the positive y direction. how much work is done on the canister by the 3.0 n force during this time?

44.58 J

Explanation:

mass of block

Force magnitude=3 N

Initial velocity =

Final velocity=

Initial Kinetic Energy=

=

Final Kinetic Energy=

=

Work Done =Final -Initial Kinetic energy=51.2-6.612=44.58 J

and 1and 1

another example of kinetic energy would be,

kinetic energy   >     moving energy

answer   >   letter choice (c),   a hammer falling off a table.

hope that !                                         : )