On an inclined plane with angle α to the horizontal it leans a rod which, due to a guide, it can move only vertically. find the velocity "u" with which will climb the rod when the inclined plane is moved to the left with the constant velocity "v".
v, alpha

u=?
me with explanations and a draw i don't get it when in decomposition of "u" what vector it will have the value = value of v and i don't know how to recognize the alpha angle in the decomposition.

u = - tan * v

Explanation:

Here is a different perspective. An observer that moves along the incline has a velocity w. The velocity v of the incline is equal to the horizontal componant of the observer with the opposit sign. The velocity u of the rod is the vertical component of the observer.

You get the following equations:

u = w sin

v = - w cos

Dividing both equations give:

u/v = -tan

u = - tan * v

r=rho l/a where a is the area, l is the length and rho is resistivity so the greater the area the lesser the resistance thats why the earth pin is thicker bcos current follow the shortest path, so less resistive .

0.11 m/s and 0.28 m/s should be correct