An airplane takes 4 hours to travel a distance of 3600 miles with the wind. the return trip takes 5 hours against the wind. find the speed of the plane in still air and the speed of the wind.

wind speed = 90 mi/h

aircraft speed = 810 mi/h

Explanation:

Let the speed of the airplane be u and the wind speed be w.

The distance d traveled is given by: d = speed * time

1. trip:

d = 3600 miles, time t = 4 h, speed = u + w

3600 = (u + w) * 4

2. trip:

d = 3600 miles, time t = 5 h, speed = u - w

3600 = (u -w) * 5

You have two equations with two unknown. Solve for u and w.

For example:

(u + w) * 4 = (u - w) * 5

4u + 4w = 5u - 5w

u = 9w

Plugging this result in one of the equations gives:

3600 = (9w + w) * 4

3600 = 10w * 4

w = 90 mi/h

u = 810 mi/h

explanation:

a fuel engine ( known as a gasoline engine in american english )is an internal combustion engine with spark ignition, designed to run on petrol (gasoline) and similar volatile fuels.

force tends to be low and long diustance masses are high